(-x^2+1)*(x^2-3x+2)=0

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Solution for (-x^2+1)*(x^2-3x+2)=0 equation:


Simplifying
(-1x2 + 1)(x2 + -3x + 2) = 0

Reorder the terms:
(1 + -1x2)(x2 + -3x + 2) = 0

Reorder the terms:
(1 + -1x2)(2 + -3x + x2) = 0

Multiply (1 + -1x2) * (2 + -3x + x2)
(1(2 + -3x + x2) + -1x2 * (2 + -3x + x2)) = 0
((2 * 1 + -3x * 1 + x2 * 1) + -1x2 * (2 + -3x + x2)) = 0
((2 + -3x + 1x2) + -1x2 * (2 + -3x + x2)) = 0
(2 + -3x + 1x2 + (2 * -1x2 + -3x * -1x2 + x2 * -1x2)) = 0
(2 + -3x + 1x2 + (-2x2 + 3x3 + -1x4)) = 0

Combine like terms: 1x2 + -2x2 = -1x2
(2 + -3x + -1x2 + 3x3 + -1x4) = 0

Solving
2 + -3x + -1x2 + 3x3 + -1x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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